What is 3-5sqrt(x)>-2 ?

The solution to 3-5sqrt(x)>-2 is 0<= x<1

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3-5sqrt(x)>-2

3 - 5 x > - 2

0 \leq x < 1

Interval Notation

[0, 1)

Solution steps

3 - 5 x > - 2

Move

3

to the right side

- 5 x > - 5

Multiply both sides by

- 1

5 x < 5

Divide both sides by

5

x < 1

Square both sides

(x)^{2} < 1^{2}

Simplify

x < 1

Find singularity points

Find non-negative values for radicals:

x \geq 0

Combine the intervals

x < 1 and x \geq 0

Merge Overlapping Intervals

0 \leq x < 1

ln (- 3)

4 x^{2} - 12 x - 11 = 0

- 3.1 x^{2} + 4.5 x - 19.9 = 750

lo g_{6} (\frac{1}{216}) = x

2 a^{2} - 3 ab - 2 b^{2}