What is the answer to 9^{x^2+x}=27^{x^2-1} ?

The answer to 9^{x^2+x}=27^{x^2-1} is x=-1,x=3

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9^{x^2+x}=27^{x^2-1}

9^{x^{2} + x} = 2 7^{x^{2} - 1}

x = - 1, x = 3

Solution steps

9^{x^{2} + x} = 2 7^{x^{2} - 1}

Apply exponent rules

2 (x^{2} + x) = 3 (x^{2} - 1)

Solve

2 (x^{2} + x) = 3 (x^{2} - 1) : x = - 1, x = 3

x = - 1, x = 3

2 7^{x^{2} - x - 6} = 1

6 = 4^{2 X - 1}

2^{n - 1} = 512

2^{x^{2}} = 4^{2 (x - 1)}

What is the answer to 9^{x^2+x}=27^{x^2-1} ?
The answer to 9^{x^2+x}=27^{x^2-1} is x=-1,x=3
Solve for x: 9^{x^2+x}=27^{x^2-1}
The solution is x=-1,x=3