What is the answer to 57=11^x ?

The answer to 57=11^x is x=(ln(57))/(ln(11))

The solution is x=(ln(57))/(ln(11))

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57=11^x

57 = 1 1^{x}

x = \frac{ln ( 57 )}{ln ( 11 )}

Decimal Notation

x = 1.68608 \dots

Solution steps

57 = 1 1^{x}

Apply exponent rules

ln (57) = x ln (11)

Solve

ln (57) = x ln (11) : x = \frac{ln ( 57 )}{ln ( 11 )}

x = \frac{ln ( 57 )}{ln ( 11 )}

5^{x + 3} = 625

x, f = (\frac{1}{m})^{x}

3^{2 x} - 5 \cdot 3^{x} + 6 = 0

3^{x + 1} - 8 (3^{x - 1}) - 5 = 0

\frac{1}{100} = e^{- 0.15 t}