What is the answer to 3^{(-2)}*3^{(2x)}=7 ?

The answer to 3^{(-2)}*3^{(2x)}=7 is x=(ln(63))/(2ln(3))

Solve for x: 3^{(-2)}*3^{(2x)}=7

The solution is x=(ln(63))/(2ln(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{(- 2)} \cdot 3^{(2 x)} = 7

x = \frac{ln ( 63 )}{2 ln ( 3 )}

Decimal Notation

x = 1.88562 \dots

Solution steps

3^{(- 2)} \cdot 3^{(2 x)} = 7

Apply exponent rules

(2 x - 2) ln (3) = ln (7)

Solve

(2 x - 2) ln (3) = ln (7) : x = \frac{ln ( 63 )}{2 ln ( 3 )}

x = \frac{ln ( 63 )}{2 ln ( 3 )}

e^{x} = 2 x + 1

e^{x} = 2 x + 2

2^{3 x - 4} = 18

3 \cdot (2)^{x - 1} - 2 = 0

6^{2 x} + 6^{x} - 6 = 0

What is the answer to 3^{(-2)}*3^{(2x)}=7 ?
The answer to 3^{(-2)}*3^{(2x)}=7 is x=(ln(63))/(2ln(3))
Solve for x: 3^{(-2)}*3^{(2x)}=7
The solution is x=(ln(63))/(2ln(3))