What is the answer to 7^{2x}=10^{3x+1} ?

The answer to 7^{2x}=10^{3x+1} is x=(ln(10))/(2ln(7)-3ln(10))

Solve for x: 7^{2x}=10^{3x+1}

The solution is x=(ln(10))/(2ln(7)-3ln(10))

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7^{2 x} = 1 0^{3 x + 1}

x = \frac{ln ( 10 )}{2 ln ( 7 ) - 3 ln ( 10 )}

Decimal Notation

x = - 0.76347 \dots

Solution steps

7^{2 x} = 1 0^{3 x + 1}

Apply exponent rules

2 x ln (7) = (3 x + 1) ln (10)

Solve

2 x ln (7) = (3 x + 1) ln (10) : x = \frac{ln ( 10 )}{2 ln ( 7 ) - 3 ln ( 10 )}

x = \frac{ln ( 10 )}{2 ln ( 7 ) - 3 ln ( 10 )}

x, 9^{x} = 243

1 6^{\frac{2}{x}} = 2

(6^{2}) (2^{2 x - 3}) = 1 6^{x - 2}

8^{x} = 2^{6}

2^{x - 1} = 500000

What is the answer to 7^{2x}=10^{3x+1} ?
The answer to 7^{2x}=10^{3x+1} is x=(ln(10))/(2ln(7)-3ln(10))
Solve for x: 7^{2x}=10^{3x+1}
The solution is x=(ln(10))/(2ln(7)-3ln(10))