What is the answer to 3^{2x}-30*3^x+81=0 ?

The answer to 3^{2x}-30*3^x+81=0 is x=3,x=1

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3^{2x}-30*3^x+81=0

3^{2 x} - 30 \cdot 3^{x} + 81 = 0

x = 3, x = 1

Solution steps

3^{2 x} - 30 \cdot 3^{x} + 81 = 0

Apply exponent rules

(3^{x})^{2} - 30 \cdot 3^{x} + 81 = 0

Rewrite the equation with

3^{x} = u

(u)^{2} - 30 u + 81 = 0

Solve

u^{2} - 30 u + 81 = 0 : u = 27, u = 3

u = 27, u = 3

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 27 : x = 3

Solve

3^{x} = 3 : x = 1

x = 3, x = 1

(5 x + 11)^{2 x - 1} = (5 x + 11)^{x - 6}

2^{2 x} - 5 (2^{x}) + 6 = 0

a^{a} = 2

e^{3 x} = 14

x, f = - 2 ((- 6)^{(x + 5)})

What is the answer to 3^{2x}-30*3^x+81=0 ?
The answer to 3^{2x}-30*3^x+81=0 is x=3,x=1
Solve for x: 3^{2x}-30*3^x+81=0
The solution is x=3,x=1