What is the answer to 12^x=xlog_{10}(12) ?

The answer to 12^x=xlog_{10}(12) is No Solution for x\in\mathbb{R}

Solve for x: 12^x=xlog_{10}(12)

The solution is No Solution for x\in\mathbb{R}

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1 2^{x} = x lo g_{10} (12)

No Solution for x \in R

Solution steps

1 2^{x} = x lo g_{10} (12)

Prepare

1 2^{x} = x lo g_{10} (12)

for Lambert form:

1 = x lo g_{10} (12) e^{- l n (12) x}

Rewrite the equation with

- x ln (12) = u

and

x = - \frac{u}{ln ( 12 )}

1 = (- \frac{u}{ln ( 12 )}) lo g_{10} (12) e^{u}

Rewrite

1 = (- \frac{u}{ln ( 12 )}) lo g_{10} (12) e^{u}

in Lambert form:

e^{u} u = - \frac{ln ( 12 )}{lo g _{10} ( 12 )}

Solve

e^{u} u = - \frac{ln ( 12 )}{lo g _{10} ( 12 )} :

No Solution for

u \in R

No Solution for x \in R

59 = 2 7^{x}

7^{8} + 7^{9} = 8 \cdot 7^{x}

mn = a^{x}

7^{x + 1} + 7^{1 - x} = 50

x, y^{x} = 5

What is the answer to 12^x=xlog_{10}(12) ?
The answer to 12^x=xlog_{10}(12) is No Solution for x\in\mathbb{R}
Solve for x: 12^x=xlog_{10}(12)
The solution is No Solution for x\in\mathbb{R}