What is the answer to solvefor x,4^x+2^{(x+2)}=32 ?

The answer to solvefor x,4^x+2^{(x+2)}=32 is x=2

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solvefor x,4^x+2^{(x+2)}=32

solve for

x, 4^{x} + 2^{(x + 2)} = 32

x = 2

Solution steps

4^{x} + 2^{(x + 2)} = 32

Apply exponent rules

(2^{x})^{2} + 2^{x} \cdot 2^{2} = 32

Rewrite the equation with

2^{x} = u

(u)^{2} + u \cdot 2^{2} = 32

Solve

u^{2} + u \cdot 2^{2} = 32 : u = 4, u = - 8

u = 4, u = - 8

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 4 : x = 2

Solve

2^{x} = - 8 :

No Solution for

x \in R

x = 2

4 \cdot e^{- 7 a - 5} = - 9

23 \cdot 3^{2 x} = 115

(3^{x})^{3} = 2 7^{x}

\frac{( 2 ^{n} )}{n + 1} = 51.2

8^{x - 9} = (\frac{1}{2})^{x + 1}

What is the answer to solvefor x,4^x+2^{(x+2)}=32 ?
The answer to solvefor x,4^x+2^{(x+2)}=32 is x=2