What is the answer to 0=3e^{3x}(10-6x)+e^{3x}(-6) ?

The answer to 0=3e^{3x}(10-6x)+e^{3x}(-6) is x= 4/3

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0=3e^{3x}(10-6x)+e^{3x}(-6)

0 = 3 e^{3 x} (10 - 6 x) + e^{3 x} (- 6)

x = \frac{4}{3}

Decimal Notation

x = 1.33333 \dots

Solution steps

0 = 3 e^{3 x} (10 - 6 x) + e^{3 x} (- 6)

Factor

0 = - 6 e^{3 x} (3 x - 4)

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

e^{3 x} = 0 or 3 x - 4 = 0

Solve

e^{3 x} = 0 :

No Solution for

x \in R

Solve

3 x - 4 = 0 : x = \frac{4}{3}

x = \frac{4}{3}

\frac{1}{5} = e^{- 3 t}

2 (3^{2 x}) + 7 (3^{x}) - 15 = 0

5^{2 x - 5} = 125

4 = (4096)^{\frac{1}{k + 1}}

t, a = b (1 - e^{- k t})

What is the answer to 0=3e^{3x}(10-6x)+e^{3x}(-6) ?
The answer to 0=3e^{3x}(10-6x)+e^{3x}(-6) is x= 4/3