What is the answer to 4^{3x}=2^{2x-6} ?

The answer to 4^{3x}=2^{2x-6} is x=-3/2

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4^{3x}=2^{2x-6}

4^{3 x} = 2^{2 x - 6}

x = - \frac{3}{2}

Decimal Notation

x = - 1.5

Solution steps

4^{3 x} = 2^{2 x - 6}

Apply exponent rules

6 x = 2 x - 6

Solve

6 x = 2 x - 6 : x = - \frac{3}{2}

x = - \frac{3}{2}

14 4^{(2 x + 1)} = 1 2^{(5 x - 1)}

4^{x + 3} - 4^{x} = A \cdot 4^{x}

x, e^{3 - 4 x} = 9

5 e^{x} = 137

x, 3^{3 x} = 7^{2 x + 1}