What is the answer to (2x+4)^{5-x}=(2x+4)^{3-2x} ?

The answer to (2x+4)^{5-x}=(2x+4)^{3-2x} is x=-3/2

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(2x+4)^{5-x}=(2x+4)^{3-2x}

(2 x + 4)^{5 - x} = (2 x + 4)^{3 - 2 x}

x = - \frac{3}{2}

Decimal Notation

x = - 1.5

Solution steps

(2 x + 4)^{5 - x} = (2 x + 4)^{3 - 2 x}

Apply exponent rules

(5 - x) ln (2 x + 4) = (3 - 2 x) ln (2 x + 4)

Solve

(5 - x) ln (2 x + 4) = (3 - 2 x) ln (2 x + 4) : x = - \frac{3}{2}

x = - \frac{3}{2}

e^{x} = 0.4

e^{l n (3 x)} = 11

40000 = 2^{t} \cdot 100

2 e^{4 x} + 7 = 12

n, (1 - 0.99)^{n} = 0.01

What is the answer to (2x+4)^{5-x}=(2x+4)^{3-2x} ?
The answer to (2x+4)^{5-x}=(2x+4)^{3-2x} is x=-3/2
Solve for x: (2x+4)^{5-x}=(2x+4)^{3-2x}
The solution is x=-3/2