What is the answer to 1000=7*1.1^{n-1} ?

The answer to 1000=7*1.1^{n-1} is n=(ln(1000/7))/(ln(1.1))+1

Solve for n: 1000=7*1.1^{n-1}

The solution is n=(ln(1000/7))/(ln(1.1))+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1000 = 7 \cdot 1. 1^{n - 1}

n = \frac{ln ( \frac{1000}{7} )}{ln ( 1.1 )} + 1

Decimal Notation

n = 53.05997 \dots

Solution steps

1000 = 7 \cdot 1. 1^{n - 1}

Switch sides

7 \cdot 1. 1^{n - 1} = 1000

Divide both sides by

7

1. 1^{n - 1} = \frac{1000}{7}

Apply exponent rules

(n - 1) ln (1.1) = ln (\frac{1000}{7})

Solve

(n - 1) ln (1.1) = ln (\frac{1000}{7}) : n = \frac{ln ( \frac{1000}{7} )}{ln ( 1.1 )} + 1

n = \frac{ln ( \frac{1000}{7} )}{ln ( 1.1 )} + 1

3^{2 x + 8} = 9^{3 x - 10}

5 \cdot 2^{3 x + 1} = 30

e^{- x^{2}} (1 - 2 x^{2}) = 0

n, (x^{4})^{n} = x^{16}

\frac{10 0 ^{x} - 1}{1 0 ^{x} + 1} = 9

What is the answer to 1000=7*1.1^{n-1} ?
The answer to 1000=7*1.1^{n-1} is n=(ln(1000/7))/(ln(1.1))+1
Solve for n: 1000=7*1.1^{n-1}
The solution is n=(ln(1000/7))/(ln(1.1))+1