What is the answer to 3^{2x-2}=sqrt(3) ?

The answer to 3^{2x-2}=sqrt(3) is x= 5/4

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3^{2x-2}=sqrt(3)

3^{2 x - 2} = 3

x = \frac{5}{4}

Decimal Notation

x = 1.25

Solution steps

3^{2 x - 2} = 3

Apply exponent rules

2 x - 2 = \frac{1}{2}

Solve

2 x - 2 = \frac{1}{2} : x = \frac{5}{4}

x = \frac{5}{4}

x, e^{x} + e^{- x} = 2 y

\frac{3 ^{1}}{x} = (2 7^{x})^{2}

3^{x} \cdot 2^{x} = 216

3^{1 - x} = 2 7^{- 1}

(\frac{8}{7})^{x} = 5^{1 - x}

What is the answer to 3^{2x-2}=sqrt(3) ?
The answer to 3^{2x-2}=sqrt(3) is x= 5/4
Solve for x: 3^{2x-2}=sqrt(3)
The solution is x= 5/4