What is the answer to (sqrt(2))^x=4^{x+2} ?

The answer to (sqrt(2))^x=4^{x+2} is x=-8/3

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(sqrt(2))^x=4^{x+2}

(2)^{x} = 4^{x + 2}

x = - \frac{8}{3}

Decimal Notation

x = - 2.66666 \dots

Solution steps

(2)^{x} = 4^{x + 2}

Apply exponent rules

\frac{1}{2} x = 2 (x + 2)

Solve

\frac{1}{2} x = 2 (x + 2) : x = - \frac{8}{3}

x = - \frac{8}{3}

lo g_{2} (2^{x + 1}) = 4

2 7^{5} = 3^{4 m + 3}

0.1 x + e^{0.25 x} = 2

2 = 2^{y}

e^{6} x = 6 e^{x}

What is the answer to (sqrt(2))^x=4^{x+2} ?
The answer to (sqrt(2))^x=4^{x+2} is x=-8/3
Solve for x: (sqrt(2))^x=4^{x+2}
The solution is x=-8/3