What is the answer to (4^{x+1})/(2^{3x-2)}=256 ?

The answer to (4^{x+1})/(2^{3x-2)}=256 is x=-4

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(4^{x+1})/(2^{3x-2)}=256

\frac{4 ^{x + 1}}{2 ^{3 x - 2}} = 256

x = - 4

Solution steps

\frac{4 ^{x + 1}}{2 ^{3 x - 2}} = 256

Apply exponent rules

2 (x + 1) - 3 x + 2 = 8

Solve

2 (x + 1) - 3 x + 2 = 8 : x = - 4

x = - 4

Verify Solutions:

x = - 4

True

The solution is

x = - 4

x, 6^{x} = 2 \cdot y

x, 2^{x + 1} = 5^{1 - 2 x}

5^{6} \cdot 5^{m} = 5^{2 m} \cdot 5

2^{- (x + 3)} = 3 2^{x}

(5^{x})^{3} = 25 \cdot 12 5^{x}

What is the answer to (4^{x+1})/(2^{3x-2)}=256 ?
The answer to (4^{x+1})/(2^{3x-2)}=256 is x=-4
Solve for x: (4^{x+1})/(2^{3x-2)}=256
The solution is x=-4