What is the answer to 3^{x+2}-3^{x+1}+3^x=63 ?

The answer to 3^{x+2}-3^{x+1}+3^x=63 is x=2

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3^{x+2}-3^{x+1}+3^x=63

3^{x + 2} - 3^{x + 1} + 3^{x} = 63

x = 2

Solution steps

3^{x + 2} - 3^{x + 1} + 3^{x} = 63

Factor

3^{x + 2} - 3^{x + 1} + 3^{x} : 7 \cdot 3^{x}

7 \cdot 3^{x} = 63

Divide both sides by

7

3^{x} = 9

Apply exponent rules

x = 2

3^{x + 4} = 9

5^{2 x - 1} = \frac{1}{125}

(\frac{1}{2})^{x} + 2 = 3

2^{n^{2}} = 2^{n + 6}

e^{6 x} - 6 e^{3 x} + 6 = 0

What is the answer to 3^{x+2}-3^{x+1}+3^x=63 ?
The answer to 3^{x+2}-3^{x+1}+3^x=63 is x=2
Solve for x: 3^{x+2}-3^{x+1}+3^x=63
The solution is x=2