What is the answer to 7^{4x+3}=21 ?

The answer to 7^{4x+3}=21 is x=(ln(3/49))/(4ln(7))

Solve for x: 7^{4x+3}=21

The solution is x=(ln(3/49))/(4ln(7))

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7^{4 x + 3} = 21

x = \frac{ln ( \frac{3}{49} )}{4 ln ( 7 )}

Decimal Notation

x = - 0.35885 \dots

Solution steps

7^{4 x + 3} = 21

Apply exponent rules

(4 x + 3) ln (7) = ln (21)

Solve

(4 x + 3) ln (7) = ln (21) : x = \frac{ln ( \frac{3}{49} )}{4 ln ( 7 )}

x = \frac{ln ( \frac{3}{49} )}{4 ln ( 7 )}

(100)^{x} = 1

k, 10.5 = 15 (1 - e^{- 40 k})

\frac{8}{2 ^{n}} = 2

4^{x + 1} = 0.25

450000 = 200000 (1 + 0.12)^{x}

What is the answer to 7^{4x+3}=21 ?
The answer to 7^{4x+3}=21 is x=(ln(3/49))/(4ln(7))
Solve for x: 7^{4x+3}=21
The solution is x=(ln(3/49))/(4ln(7))