What is the answer to 5^x-2-5^x+5^x+1=5 ?

The answer to 5^x-2-5^x+5^x+1=5 is x=(ln(6))/(ln(5))

Solve for x: 5^x-2-5^x+5^x+1=5

The solution is x=(ln(6))/(ln(5))

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5^{x} - 2 - 5^{x} + 5^{x} + 1 = 5

x = \frac{ln ( 6 )}{ln ( 5 )}

Decimal Notation

x = 1.11328 \dots

Solution steps

5^{x} - 2 - 5^{x} + 5^{x} + 1 = 5

Group like terms

5^{x} - 5^{x} + 5^{x} - 2 + 1 = 5

Add similar elements:

5^{x} - 5^{x} + 5^{x} = 5^{x}

5^{x} - 2 + 1 = 5

Add/Subtract the numbers:

- 2 + 1 = - 1

5^{x} - 1 = 5

Move

1

to the right side

5^{x} = 6

Apply exponent rules

x ln (5) = ln (6)

Solve

x ln (5) = ln (6) : x = \frac{ln ( 6 )}{ln ( 5 )}

x = \frac{ln ( 6 )}{ln ( 5 )}

6^{7 x} = 8

e^{x} + 20 e^{- x} = 9

7^{3 x + 7} = 7

x, (- 1)^{x} = y

a^{x} = b \cdot c

What is the answer to 5^x-2-5^x+5^x+1=5 ?
The answer to 5^x-2-5^x+5^x+1=5 is x=(ln(6))/(ln(5))
Solve for x: 5^x-2-5^x+5^x+1=5
The solution is x=(ln(6))/(ln(5))