What is the answer to 4^{2x+1}*5^{x-2}=6^{1-x} ?

The answer to 4^{2x+1}*5^{x-2}=6^{1-x} is x=(ln(75/2))/(ln(480))

Solve for x: 4^{2x+1}*5^{x-2}=6^{1-x}

The solution is x=(ln(75/2))/(ln(480))

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4^{2 x + 1} \cdot 5^{x - 2} = 6^{1 - x}

x = \frac{ln ( \frac{75}{2} )}{ln ( 480 )}

Decimal Notation

x = 0.58705 \dots

Solution steps

4^{2 x + 1} \cdot 5^{x - 2} = 6^{1 - x}

Apply exponent rules

(2 x + 1 + lo g_{4} (5) (x - 2)) ln (4) = (1 - x) ln (6)

Solve

(2 x + 1 + lo g_{4} (5) (x - 2)) ln (4) = (1 - x) ln (6) : x = \frac{ln ( \frac{75}{2} )}{ln ( 480 )}

x = \frac{ln ( \frac{75}{2} )}{ln ( 480 )}

x 9 = 8 + x + e^{x}

8^{- 9^{x^{- 1}}} = \frac{1}{2}

1.005 7^{4 t} = 2.22717

0. 3^{x} = 4^{x^{2}}

4^{2 x - 6} = 48

What is the answer to 4^{2x+1}*5^{x-2}=6^{1-x} ?
The answer to 4^{2x+1}*5^{x-2}=6^{1-x} is x=(ln(75/2))/(ln(480))
Solve for x: 4^{2x+1}*5^{x-2}=6^{1-x}
The solution is x=(ln(75/2))/(ln(480))