What is the answer to solvefor y,x=2^{3-y} ?

The answer to solvefor y,x=2^{3-y} is y=-(ln(x)-3ln(2))/(ln(2))

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solvefor y,x=2^{3-y}

solve for

y, x = 2^{3 - y}

y = - \frac{ln ( x ) - 3 ln ( 2 )}{ln ( 2 )}

Solution steps

x = 2^{3 - y}

Apply exponent rules

ln (x) = (3 - y) ln (2)

Solve

ln (x) = (3 - y) ln (2) : y = - \frac{ln ( x ) - 3 ln ( 2 )}{ln ( 2 )}

y = - \frac{ln ( x ) - 3 ln ( 2 )}{ln ( 2 )}

9^{3 m + 1} = 27

\frac{6 ^{p}}{6 ^{5}} = 6

x, 9^{- x} = 81

0.98 = 1 - e^{- \frac{t}{0.1}}

4^{2 x} - 5 \cdot 4^{x + 2} + 1021 = 0

What is the answer to solvefor y,x=2^{3-y} ?
The answer to solvefor y,x=2^{3-y} is y=-(ln(x)-3ln(2))/(ln(2))