What is the answer to 3^x=7^{1-x} ?

The answer to 3^x=7^{1-x} is x=(ln(7))/(ln(21))

Solve for x: 3^x=7^{1-x}

The solution is x=(ln(7))/(ln(21))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{x} = 7^{1 - x}

x = \frac{ln ( 7 )}{ln ( 21 )}

Decimal Notation

x = 0.63915 \dots

Solution steps

3^{x} = 7^{1 - x}

Apply exponent rules

x ln (3) = (1 - x) ln (7)

Solve

x ln (3) = (1 - x) ln (7) : x = \frac{ln ( 7 )}{ln ( 21 )}

x = \frac{ln ( 7 )}{ln ( 21 )}

x, 3^{x} = 4 y

4^{2 x} + 4^{x} - 20 = 0

x, e^{(- x - y)} = 0

5 (2^{x}) = 240

4^{x} + 4^{x} + 4^{x} + 4^{x} = 4^{16}

What is the answer to 3^x=7^{1-x} ?
The answer to 3^x=7^{1-x} is x=(ln(7))/(ln(21))
Solve for x: 3^x=7^{1-x}
The solution is x=(ln(7))/(ln(21))