What is the answer to 24(3^{-y})=16(2^{2y}) ?

The answer to 24(3^{-y})=16(2^{2y}) is y=-(ln(2/3))/(ln(12))

Solve for y: 24(3^{-y})=16(2^{2y})

The solution is y=-(ln(2/3))/(ln(12))

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24 (3^{- y}) = 16 (2^{2 y})

y = - \frac{ln ( \frac{2}{3} )}{ln ( 12 )}

Decimal Notation

y = 0.16317 \dots

Solution steps

24 (3^{- y}) = 16 (2^{2 y})

Apply exponent rules

ln (24) - y ln (3) = ln (16) + 2 y ln (2)

Solve

ln (24) - y ln (3) = ln (16) + 2 y ln (2) : y = - \frac{ln ( \frac{2}{3} )}{ln ( 12 )}

y = - \frac{ln ( \frac{2}{3} )}{ln ( 12 )}

2 e^{- x} = 0

2 e^{- x} = 1

1 0^{l o g_{10} (x + 1)} = 1

(\frac{1}{4})^{4 x} = \frac{1}{4}

5^{2 x - 1} = 1953125

What is the answer to 24(3^{-y})=16(2^{2y}) ?
The answer to 24(3^{-y})=16(2^{2y}) is y=-(ln(2/3))/(ln(12))
Solve for y: 24(3^{-y})=16(2^{2y})
The solution is y=-(ln(2/3))/(ln(12))