What is the answer to 2^{x-1}=(4^2)^{x+1} ?

The answer to 2^{x-1}=(4^2)^{x+1} is x=-5/3

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2^{x-1}=(4^2)^{x+1}

2^{x - 1} = (4^{2})^{x + 1}

x = - \frac{5}{3}

Decimal Notation

x = - 1.66666 \dots

Solution steps

2^{x - 1} = (4^{2})^{x + 1}

Apply exponent rules

x - 1 = 4 (x + 1)

Solve

x - 1 = 4 (x + 1) : x = - \frac{5}{3}

x = - \frac{5}{3}

2^{m + 1} = 1 6^{m + 7}

5^{3 x + 4} = 40

5^{3 x + 4} = 35

5^{3 x + 4} = 20

5^{x} - 625 = 0

What is the answer to 2^{x-1}=(4^2)^{x+1} ?
The answer to 2^{x-1}=(4^2)^{x+1} is x=-5/3
Solve for x: 2^{x-1}=(4^2)^{x+1}
The solution is x=-5/3