What is the answer to 7^{3x+2}=140 ?

The answer to 7^{3x+2}=140 is x=(ln(20/7))/(3ln(7))

Solve for x: 7^{3x+2}=140

The solution is x=(ln(20/7))/(3ln(7))

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7^{3 x + 2} = 140

x = \frac{ln ( \frac{20}{7} )}{3 ln ( 7 )}

Decimal Notation

x = 0.17983 \dots

Solution steps

7^{3 x + 2} = 140

Apply exponent rules

(3 x + 2) ln (7) = ln (140)

Solve

(3 x + 2) ln (7) = ln (140) : x = \frac{ln ( \frac{20}{7} )}{3 ln ( 7 )}

x = \frac{ln ( \frac{20}{7} )}{3 ln ( 7 )}

4^{- 0.2 x} + 1 = 0

1 6^{(x^{2})} = 4^{6 x - 4}

1.5 = e^{k \cdot \frac{1}{2}}

e^{2 k} = 25

e^{5 x} = e^{10 x}

What is the answer to 7^{3x+2}=140 ?
The answer to 7^{3x+2}=140 is x=(ln(20/7))/(3ln(7))
Solve for x: 7^{3x+2}=140
The solution is x=(ln(20/7))/(3ln(7))