What is the answer to 10000=3500(1.1)^b ?

The answer to 10000=3500(1.1)^b is b=(ln(20/7))/(ln(1.1))

Solve for b: 10000=3500(1.1)^b

The solution is b=(ln(20/7))/(ln(1.1))

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10000 = 3500 (1.1)^{b}

b = \frac{ln ( \frac{20}{7} )}{ln ( 1.1 )}

Decimal Notation

b = 11.01479 \dots

Solution steps

10000 = 3500 (1.1)^{b}

Switch sides

3500 \cdot 1. 1^{b} = 10000

Divide both sides by

3500

1. 1^{b} = \frac{20}{7}

Apply exponent rules

b ln (1.1) = ln (\frac{20}{7})

Solve

b ln (1.1) = ln (\frac{20}{7}) : b = \frac{ln ( \frac{20}{7} )}{ln ( 1.1 )}

b = \frac{ln ( \frac{20}{7} )}{ln ( 1.1 )}

x = 4^{x}

8^{x - 8} = 9

e^{x^{2}} - e^{5} e^{x - 1} = 0

11 (3 + e^{- x})^{- 1} = 2

11 (3 + e^{- x})^{- 1} = 3

What is the answer to 10000=3500(1.1)^b ?
The answer to 10000=3500(1.1)^b is b=(ln(20/7))/(ln(1.1))
Solve for b: 10000=3500(1.1)^b
The solution is b=(ln(20/7))/(ln(1.1))