What is the answer to 2=(1+0.09)^x ?

The answer to 2=(1+0.09)^x is x=(ln(2))/(ln(1.09))

Solve for x: 2=(1+0.09)^x

The solution is x=(ln(2))/(ln(1.09))

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2 = (1 + 0.09)^{x}

x = \frac{ln ( 2 )}{ln ( 1.09 )}

Decimal Notation

x = 8.04323 \dots

Solution steps

2 = (1 + 0.09)^{x}

Apply exponent rules

ln (2) = x ln (1 + 0.09)

Solve

ln (2) = x ln (1 + 0.09) : x = \frac{ln ( 2 )}{ln ( 1.09 )}

x = \frac{ln ( 2 )}{ln ( 1.09 )}

9^{x} - 10 (9^{x}) + 9 = 0

\frac{1}{e ^{y}} = - e^{- y}

4^{3 x - 3} = 2^{x^{3}}

2^{x} = 3^{2 x + 1}

26 = 3 (5)^{0.75 x} - 8

What is the answer to 2=(1+0.09)^x ?
The answer to 2=(1+0.09)^x is x=(ln(2))/(ln(1.09))
Solve for x: 2=(1+0.09)^x
The solution is x=(ln(2))/(ln(1.09))