What is the answer to 65=33^x ?

The answer to 65=33^x is x=(ln(65))/(ln(33))

The solution is x=(ln(65))/(ln(33))

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65=33^x

65 = 3 3^{x}

x = \frac{ln ( 65 )}{ln ( 33 )}

Decimal Notation

x = 1.19387 \dots

Solution steps

65 = 3 3^{x}

Apply exponent rules

ln (65) = x ln (33)

Solve

ln (65) = x ln (33) : x = \frac{ln ( 65 )}{ln ( 33 )}

x = \frac{ln ( 65 )}{ln ( 33 )}

3^{3 x - 2} = 21

2^{x} - 3 = \frac{1}{8}

4^{x + 2} = 4^{5}

(e)^{z} = - 2

2^{2 x + 5} 0. 6^{x} = 1 2^{x}