What are the solutions to the equation x^2-2x-3/2 =0 ?

The solutions to the equation x^2-2x-3/2 =0 are x=(2+sqrt(10))/2 ,x=(2-sqrt(10))/2

Find the zeros of x^2-2x-3/2 =0

The zeros of x^2-2x-3/2 =0 are x=(2+sqrt(10))/2 ,x=(2-sqrt(10))/2

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x^{2} - 2 x - \frac{3}{2} = 0

x = \frac{2 + 10}{2}, x = \frac{2 - 10}{2}

Decimal Notation

x = 2.58113 \dots, x = - 0.58113 \dots

Solution steps

x^{2} - 2 x - \frac{3}{2} = 0

Multiply both sides by

2

2 x^{2} - 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 3) = 210

x_{1, 2} = \frac{- ( - 4 ) \pm 2 10}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 10}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 2 10}{2 \cdot 2}

x = \frac{- ( - 4 ) + 2 10}{2 \cdot 2} : \frac{2 + 10}{2}

x = \frac{- ( - 4 ) - 2 10}{2 \cdot 2} : \frac{2 - 10}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 10}{2}, x = \frac{2 - 10}{2}

240 \cdot \frac{π}{180}

x^{2} + 2 x + 1 = - 15

4 x + 3 = 0

\frac{9}{8} + \frac{7}{40}

\frac{9 i}{- 3 + 4 i}

What are the solutions to the equation x^2-2x-3/2 =0 ?
The solutions to the equation x^2-2x-3/2 =0 are x=(2+sqrt(10))/2 ,x=(2-sqrt(10))/2
Find the zeros of x^2-2x-3/2 =0
The zeros of x^2-2x-3/2 =0 are x=(2+sqrt(10))/2 ,x=(2-sqrt(10))/2