What is the answer to (sqrt(3))^{3-x}=9^{x+2} ?

The answer to (sqrt(3))^{3-x}=9^{x+2} is x=-1

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(sqrt(3))^{3-x}=9^{x+2}

(3)^{3 - x} = 9^{x + 2}

x = - 1

Solution steps

(3)^{3 - x} = 9^{x + 2}

Apply exponent rules

\frac{1}{2} (3 - x) = 2 (x + 2)

Solve

\frac{1}{2} (3 - x) = 2 (x + 2) : x = - 1

x = - 1

2^{n} = 16

e^{x} + 5 = 0

x, 5^{8 x} = 8^{8 x - 5}

75 = 3 3^{x}

4^{x} = 3 (2)^{x}

What is the answer to (sqrt(3))^{3-x}=9^{x+2} ?
The answer to (sqrt(3))^{3-x}=9^{x+2} is x=-1
Solve for x: (sqrt(3))^{3-x}=9^{x+2}
The solution is x=-1