What is the answer to solvefor x,6^{x+2}=5^{x-2} ?

The answer to solvefor x,6^{x+2}=5^{x-2} is x=-(2ln(30))/(ln(6)-ln(5))

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solvefor x,6^{x+2}=5^{x-2}

solve for

x, 6^{x + 2} = 5^{x - 2}

x = - \frac{2 ln ( 30 )}{ln ( 6 ) - ln ( 5 )}

Decimal Notation

x = - 37.30987 \dots

Solution steps

6^{x + 2} = 5^{x - 2}

Apply exponent rules

(x + 2) ln (6) = (x - 2) ln (5)

Solve

(x + 2) ln (6) = (x - 2) ln (5) : x = - \frac{2 ln ( 30 )}{ln ( 6 ) - ln ( 5 )}

x = - \frac{2 ln ( 30 )}{ln ( 6 ) - ln ( 5 )}

8^{x} = 2^{3 x}

b, a^{2 b} = 5

5 = 5^{x}

160000 \cdot 0.9 5^{x} = 50000

What is the answer to solvefor x,6^{x+2}=5^{x-2} ?
The answer to solvefor x,6^{x+2}=5^{x-2} is x=-(2ln(30))/(ln(6)-ln(5))