What is the answer to 4^x-4^{((2x+3))/2}=-7 ?

The answer to 4^x-4^{((2x+3))/2}=-7 is x=0

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4^x-4^{((2x+3))/2}=-7

4^{x} - 4^{\frac{( 2 x + 3 )}{2}} = - 7

x = 0

Solution steps

4^{x} - 4^{\frac{( 2 x + 3 )}{2}} = - 7

Factor

4^{x} - 4^{\frac{2 x + 3}{2}} : - 7 \cdot 4^{x}

- 7 \cdot 4^{x} = - 7

Divide both sides by

- 7

4^{x} = 1

Apply exponent rules

x ln (4) = ln (1)

Solve

x ln (4) = ln (1) : x = 0

x = 0

27 (3^{2 x}) + 80 (3^{x}) - 3 = 0

x, e^{y - x^{2}} = 0

x, e^{y - x^{2}} = k

3^{x - 2} = 2^{x}

(\frac{1}{5})^{x} = 10

What is the answer to 4^x-4^{((2x+3))/2}=-7 ?
The answer to 4^x-4^{((2x+3))/2}=-7 is x=0
Solve for x: 4^x-4^{((2x+3))/2}=-7
The solution is x=0