What is the answer to |x^2-1|+|x^2-16|=4 ?

The answer to |x^2-1|+|x^2-16|=4 is No Solution for x\in\mathbb{R}

Solve for x: |x^2-1|+|x^2-16|=4

The solution is No Solution for x\in\mathbb{R}

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Popular >

x^{2} - 1 + x^{2} - 16 = 4

No Solution for x \in R

Solution steps

x^{2} - 1 + x^{2} - 16 = 4

Find positive and negative intervals

x \leq - 4, - 4 < x \leq - 1, - 1 < x < 1, 1 \leq x < 4, x \geq 4

Solve the inequality for each interval

No Solution for x \in R

8 x^{2} - 10 x + 15 = 0

- 2 x^{2} + 9 x + 5

32 - 8

\frac{7 + 5}{6 - 5}

What is the answer to |x^2-1|+|x^2-16|=4 ?
The answer to |x^2-1|+|x^2-16|=4 is No Solution for x\in\mathbb{R}
Solve for x: |x^2-1|+|x^2-16|=4
The solution is No Solution for x\in\mathbb{R}