What is the answer to 16^{-7x}=72 ?

The answer to 16^{-7x}=72 is x=-(ln(72))/(28ln(2))

Solve for x: 16^{-7x}=72

The solution is x=-(ln(72))/(28ln(2))

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1 6^{- 7 x} = 72

x = - \frac{ln ( 72 )}{28 ln ( 2 )}

Decimal Notation

x = - 0.22035 \dots

Solution steps

1 6^{- 7 x} = 72

Apply exponent rules

- 7 x ln (16) = ln (72)

Solve

- 7 x ln (16) = ln (72) : x = - \frac{ln ( 72 )}{28 ln ( 2 )}

x = - \frac{ln ( 72 )}{28 ln ( 2 )}

5^{2 x - 1} = 6

5^{2 x + 4} = \frac{1}{625}

3^{x - 1} + 3^{x} - 12 = 0

e^{a} = 35

4150 = 2300 (1.06)^{x}

What is the answer to 16^{-7x}=72 ?
The answer to 16^{-7x}=72 is x=-(ln(72))/(28ln(2))
Solve for x: 16^{-7x}=72
The solution is x=-(ln(72))/(28ln(2))