What is the answer to 440=402*2^x ?

The answer to 440=402*2^x is x=(ln(220/201))/(ln(2))

Solve for x: 440=402*2^x

The solution is x=(ln(220/201))/(ln(2))

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440 = 402 \cdot 2^{x}

x = \frac{ln ( \frac{220}{201} )}{ln ( 2 )}

Decimal Notation

x = 0.13030 \dots

Solution steps

440 = 402 \cdot 2^{x}

Switch sides

402 \cdot 2^{x} = 440

Divide both sides by

402

2^{x} = \frac{220}{201}

Apply exponent rules

x ln (2) = ln (\frac{220}{201})

Solve

x ln (2) = ln (\frac{220}{201}) : x = \frac{ln ( \frac{220}{201} )}{ln ( 2 )}

x = \frac{ln ( \frac{220}{201} )}{ln ( 2 )}

2.8 3^{x} = 14.1

9^{x} + 3^{x + 1} - 18 = 0

5^{x - 4} = 2 5^{x}

3 6^{4} = 3^{x} \cdot 4^{4}

4 x \cdot 8^{x} = 8

What is the answer to 440=402*2^x ?
The answer to 440=402*2^x is x=(ln(220/201))/(ln(2))
Solve for x: 440=402*2^x
The solution is x=(ln(220/201))/(ln(2))