What is the answer to 9^{x-1}=7 ?

The answer to 9^{x-1}=7 is x=(ln(7))/(2ln(3))+1

Solve for x: 9^{x-1}=7

The solution is x=(ln(7))/(2ln(3))+1

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9^{x - 1} = 7

x = \frac{ln ( 7 )}{2 ln ( 3 )} + 1

Decimal Notation

x = 1.88562 \dots

Solution steps

9^{x - 1} = 7

Apply exponent rules

(x - 1) ln (9) = ln (7)

Solve

(x - 1) ln (9) = ln (7) : x = \frac{ln ( 7 )}{2 ln ( 3 )} + 1

x = \frac{ln ( 7 )}{2 ln ( 3 )} + 1

3 e^{x} + 1 = 5

e^{2 x} + e^{3 x} = 0

1 0^{\frac{z}{3}} = 7

64 = 3 2^{- x + 1}

e^{x^{2} - 21} = e^{4}

What is the answer to 9^{x-1}=7 ?
The answer to 9^{x-1}=7 is x=(ln(7))/(2ln(3))+1
Solve for x: 9^{x-1}=7
The solution is x=(ln(7))/(2ln(3))+1