What is the answer to (3^{x+1})^2=81^{2x-4} ?

The answer to (3^{x+1})^2=81^{2x-4} is x=3

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(3^{x+1})^2=81^{2x-4}

(3^{x + 1})^{2} = 8 1^{2 x - 4}

x = 3

Solution steps

(3^{x + 1})^{2} = 8 1^{2 x - 4}

Apply exponent rules

(x + 1) \cdot 2 = 4 (2 x - 4)

Solve

(x + 1) \cdot 2 = 4 (2 x - 4) : x = 3

x = 3

5^{2 x + 3} = 30

e^{3 x} - 2 e^{2 x} + 1 = 0

5^{2 x} + 125 \cdot 5^{- 2 x} = 30

1000 = 300 + 200 e^{0.2 t}

What is the answer to (3^{x+1})^2=81^{2x-4} ?
The answer to (3^{x+1})^2=81^{2x-4} is x=3
Solve for x: (3^{x+1})^2=81^{2x-4}
The solution is x=3