What is the answer to 2^{x+4}+2^{x+2}-10=0 ?

The answer to 2^{x+4}+2^{x+2}-10=0 is x=-1

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2^{x+4}+2^{x+2}-10=0

2^{x + 4} + 2^{x + 2} - 10 = 0

x = - 1

Solution steps

2^{x + 4} + 2^{x + 2} - 10 = 0

Factor

2^{x + 4} + 2^{x + 2} - 10 : 10 (2^{1 + x} - 1)

10 (2^{1 + x} - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2^{1 + x} - 1 = 0

Solve

2^{1 + x} - 1 = 0 : x = - 1

x = - 1

8^{3 a} = 1 6^{a + 3}

2 5^{t} + 5^{t + 1} = 24

9^{1 - 2 x} = 81

9^{2 x} = \frac{1}{18}

What is the answer to 2^{x+4}+2^{x+2}-10=0 ?
The answer to 2^{x+4}+2^{x+2}-10=0 is x=-1
Solve for x: 2^{x+4}+2^{x+2}-10=0
The solution is x=-1