What is the answer to 2^{1-x}+4=9 ?

The answer to 2^{1-x}+4=9 is x=-(ln(5)-ln(2))/(ln(2))

Solve for x: 2^{1-x}+4=9

The solution is x=-(ln(5)-ln(2))/(ln(2))

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2^{1 - x} + 4 = 9

x = - \frac{ln ( 5 ) - ln ( 2 )}{ln ( 2 )}

Decimal Notation

x = - 1.32192 \dots

Solution steps

2^{1 - x} + 4 = 9

Move

4

to the right side

2^{1 - x} = 5

Apply exponent rules

(1 - x) ln (2) = ln (5)

Solve

(1 - x) ln (2) = ln (5) : x = - \frac{ln ( 5 ) - ln ( 2 )}{ln ( 2 )}

x = - \frac{ln ( 5 ) - ln ( 2 )}{ln ( 2 )}

(6^{3})^{x} = 6^{12}

e^{(- 0.25) x} = 0.98

e^{2 l n (3)} = 3^{1 - 2 x}

2 = e^{4 k}

3 x - 2 = 3^{x} + 1

What is the answer to 2^{1-x}+4=9 ?
The answer to 2^{1-x}+4=9 is x=-(ln(5)-ln(2))/(ln(2))
Solve for x: 2^{1-x}+4=9
The solution is x=-(ln(5)-ln(2))/(ln(2))