What is the answer to 1.429=2^x ?

The answer to 1.429=2^x is x=(ln(1.429))/(ln(2))

Solve for x: 1.429=2^x

The solution is x=(ln(1.429))/(ln(2))

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1.429 = 2^{x}

x = \frac{ln ( 1.429 )}{ln ( 2 )}

Decimal Notation

x = 0.51500 \dots

Solution steps

1.429 = 2^{x}

Apply exponent rules

ln (1.429) = x ln (2)

Solve

ln (1.429) = x ln (2) : x = \frac{ln ( 1.429 )}{ln ( 2 )}

x = \frac{ln ( 1.429 )}{ln ( 2 )}

37 = 9 e^{- 0.11778 x} + 22

2^{p} + 2^{p} = 2^{k}

9^{x} = 2 7^{4}

200 = 100 (2.718)^{r}

ln (\frac{2}{5}) = ln (0. 9^{t})

What is the answer to 1.429=2^x ?
The answer to 1.429=2^x is x=(ln(1.429))/(ln(2))
Solve for x: 1.429=2^x
The solution is x=(ln(1.429))/(ln(2))