What is the answer to 10^{-x}-6=51 ?

The answer to 10^{-x}-6=51 is x=-(ln(57))/(ln(10))

Solve for x: 10^{-x}-6=51

The solution is x=-(ln(57))/(ln(10))

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1 0^{- x} - 6 = 51

x = - \frac{ln ( 57 )}{ln ( 10 )}

Decimal Notation

x = - 1.75587 \dots

Solution steps

1 0^{- x} - 6 = 51

Move

6

to the right side

1 0^{- x} = 57

Apply exponent rules

- x ln (10) = ln (57)

Solve

- x ln (10) = ln (57) : x = - \frac{ln ( 57 )}{ln ( 10 )}

x = - \frac{ln ( 57 )}{ln ( 10 )}

4^{3 x - 1} = 3 \cdot 5^{x}

5^{x} = 3^{x - 2}

6^{1 - k^{2}} = 1

4 e^{x} = 25 - 25 e^{- x}

e^{x} = 2

What is the answer to 10^{-x}-6=51 ?
The answer to 10^{-x}-6=51 is x=-(ln(57))/(ln(10))
Solve for x: 10^{-x}-6=51
The solution is x=-(ln(57))/(ln(10))