What is the answer to \sqrt[3]{27^x}=32 ?

The answer to \sqrt[3]{27^x}=32 is x=(5ln(2))/(ln(3))

Solve for x: \sqrt[3]{27^x}=32

The solution is x=(5ln(2))/(ln(3))

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x = \frac{5 ln ( 2 )}{ln ( 3 )}

Decimal Notation

x = 3.15464 \dots

Solution steps

Apply exponent rules

x \frac{1}{3} ln (27) = ln (32)

Solve

x \frac{1}{3} ln (27) = ln (32) : x = \frac{5 ln ( 2 )}{ln ( 3 )}

x = \frac{5 ln ( 2 )}{ln ( 3 )}

2^{x + 3} - 2^{x} = 7 \cdot 2^{x}

8^{2 x + 3} = 2^{x}

- 4 + 4 e^{(8 x + 2.5)} = 84

e^{x^{2}} = 3

3^{x} = 9^{2 x - 1}

What is the answer to \sqrt[3]{27^x}=32 ?
The answer to \sqrt[3]{27^x}=32 is x=(5ln(2))/(ln(3))
Solve for x: \sqrt[3]{27^x}=32
The solution is x=(5ln(2))/(ln(3))