What is the answer to 2^{2x-1}=2^{2x}+2^{-1} ?

The answer to 2^{2x-1}=2^{2x}+2^{-1} is No Solution for x\in\mathbb{R}

Solve for x: 2^{2x-1}=2^{2x}+2^{-1}

The solution is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{2 x - 1} = 2^{2 x} + 2^{- 1}

No Solution for x \in R

Solution steps

2^{2 x - 1} = 2^{2 x} + 2^{- 1}

Apply exponent rules

2^{2 x} = - 1

a^{f (x)}

cannot be zero or negative for

x \in R

No Solution for x \in R

6^{4 - x} = \frac{1}{42}

6^{9 - 2 x} = 36

8^{5 x + 5} = 3 2^{2 x - 2}

1.6 = 2 e^{0.3 x}

e^{x + 8} = 26

What is the answer to 2^{2x-1}=2^{2x}+2^{-1} ?
The answer to 2^{2x-1}=2^{2x}+2^{-1} is No Solution for x\in\mathbb{R}
Solve for x: 2^{2x-1}=2^{2x}+2^{-1}
The solution is No Solution for x\in\mathbb{R}