What is the answer to 6^{(3x-5)}=27 ?

The answer to 6^{(3x-5)}=27 is x=(3ln(3)+5ln(6))/(3ln(6))

Solve for x: 6^{(3x-5)}=27

The solution is x=(3ln(3)+5ln(6))/(3ln(6))

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6^{(3 x - 5)} = 27

x = \frac{3 ln ( 3 ) + 5 ln ( 6 )}{3 ln ( 6 )}

Decimal Notation

x = 2.27981 \dots

Solution steps

6^{(3 x - 5)} = 27

Apply exponent rules

(3 x - 5) ln (6) = ln (27)

Solve

(3 x - 5) ln (6) = ln (27) : x = \frac{3 ln ( 3 ) + 5 ln ( 6 )}{3 ln ( 6 )}

x = \frac{3 ln ( 3 ) + 5 ln ( 6 )}{3 ln ( 6 )}

e^{\frac{x}{10}} + 2 = 0

(7^{4})^{5} = 1680 7^{x}

2^{2 x + 3} - 33 (2^{x}) + 4 = 0

x^{x} = 1 0^{6}

9^{2 x - 7} = \frac{1}{3}

What is the answer to 6^{(3x-5)}=27 ?
The answer to 6^{(3x-5)}=27 is x=(3ln(3)+5ln(6))/(3ln(6))
Solve for x: 6^{(3x-5)}=27
The solution is x=(3ln(3)+5ln(6))/(3ln(6))