What is the answer to 3(12)^{-3x}-5=41 ?

The answer to 3(12)^{-3x}-5=41 is x=-(ln(46/3))/(3ln(12))

Solve for x: 3(12)^{-3x}-5=41

The solution is x=-(ln(46/3))/(3ln(12))

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3 (12)^{- 3 x} - 5 = 41

x = - \frac{ln ( \frac{46}{3} )}{3 ln ( 12 )}

Decimal Notation

x = - 0.36621 \dots

Solution steps

3 (12)^{- 3 x} - 5 = 41

Move

5

to the right side

3 \cdot 1 2^{- 3 x} = 46

Divide both sides by

3

1 2^{- 3 x} = \frac{46}{3}

Apply exponent rules

- 3 x ln (12) = ln (\frac{46}{3})

Solve

- 3 x ln (12) = ln (\frac{46}{3}) : x = - \frac{ln ( \frac{46}{3} )}{3 ln ( 12 )}

x = - \frac{ln ( \frac{46}{3} )}{3 ln ( 12 )}

5 e^{3 x + 2} = 5

x^{2} - 2 x e^{- x} + e^{- 2 x} = 0

3 2^{2 x - 3} = \frac{1}{8}

2^{x + 3} = 5^{x}

What is the answer to 3(12)^{-3x}-5=41 ?
The answer to 3(12)^{-3x}-5=41 is x=-(ln(46/3))/(3ln(12))
Solve for x: 3(12)^{-3x}-5=41
The solution is x=-(ln(46/3))/(3ln(12))