What is the answer to 81^{2x-3}=9^{-x} ?

The answer to 81^{2x-3}=9^{-x} is x= 6/5

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81^{2x-3}=9^{-x}

8 1^{2 x - 3} = 9^{- x}

x = \frac{6}{5}

Decimal Notation

x = 1.2

Solution steps

8 1^{2 x - 3} = 9^{- x}

Apply exponent rules

2 (2 x - 3) = - x

Solve

2 (2 x - 3) = - x : x = \frac{6}{5}

x = \frac{6}{5}

2^{x} + 2^{x - 1} + 2^{x + 2} = 176

- 1 \cdot 2^{x - 7} + 9 = 3

4^{- x} = 2^{x + 4}

3^{200} + 3^{200} + 3^{200} = 3^{x}

lo g_{9} (8 1^{x}) = - 2

What is the answer to 81^{2x-3}=9^{-x} ?
The answer to 81^{2x-3}=9^{-x} is x= 6/5
Solve for x: 81^{2x-3}=9^{-x}
The solution is x= 6/5