What is the answer to 2^{3-5x}=4^{x^2} ?

The answer to 2^{3-5x}=4^{x^2} is x= 1/2 ,x=-3

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2^{3-5x}=4^{x^2}

2^{3 - 5 x} = 4^{x^{2}}

x = \frac{1}{2}, x = - 3

Decimal Notation

x = 0.5, x = - 3

Solution steps

2^{3 - 5 x} = 4^{x^{2}}

Apply exponent rules

3 - 5 x = 2 x^{2}

Solve

3 - 5 x = 2 x^{2} : x = \frac{1}{2}, x = - 3

x = \frac{1}{2}, x = - 3

8^{x - 1} = \frac{1}{16}

0.21 = (1.3384) e^{2.558 x}

2^{2 x - 1} - 6 \cdot 2^{x - 1} = 0

x, 2^{- x} = 0

(0.5)^{2 x - 5} = 256

What is the answer to 2^{3-5x}=4^{x^2} ?
The answer to 2^{3-5x}=4^{x^2} is x= 1/2 ,x=-3
Solve for x: 2^{3-5x}=4^{x^2}
The solution is x= 1/2 ,x=-3