What is the answer to solvefor N,F=P*(1+x)^N ?

The answer to solvefor N,F=P*(1+x)^N is N=(ln(F/P))/(ln(1+x))

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solvefor N,F=P*(1+x)^N

solve for

N, F = P \cdot (1 + x)^{N}

N = \frac{ln ( \frac{F}{P} )}{ln ( 1 + x )}

Solution steps

F = P (1 + x)^{N}

Switch sides

P (1 + x)^{N} = F

Divide both sides by

P

(1 + x)^{N} = \frac{F}{P}

Apply exponent rules

N ln (1 + x) = ln (\frac{F}{P})

Solve

N ln (1 + x) = ln (\frac{F}{P}) : N = \frac{ln ( \frac{F}{P} )}{ln ( 1 + x )}

N = \frac{ln ( \frac{F}{P} )}{ln ( 1 + x )}

2^{x} + 1 = 2 x + 5

1 6^{x} = \frac{1}{2}

45 = 3 0^{x^{6}}

y, x = e^{1 - y}

6^{5 x + 1} = 6^{7 x - 1}

What is the answer to solvefor N,F=P*(1+x)^N ?
The answer to solvefor N,F=P*(1+x)^N is N=(ln(F/P))/(ln(1+x))