What is the answer to 33^{x-2}=17^{8x} ?

The answer to 33^{x-2}=17^{8x} is x=(2ln(33))/(ln(33)-8ln(17))

Solve for x: 33^{x-2}=17^{8x}

The solution is x=(2ln(33))/(ln(33)-8ln(17))

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3 3^{x - 2} = 1 7^{8 x}

x = \frac{2 ln ( 33 )}{ln ( 33 ) - 8 ln ( 17 )}

Decimal Notation

x = - 0.36480 \dots

Solution steps

3 3^{x - 2} = 1 7^{8 x}

Apply exponent rules

(x - 2) ln (33) = 8 x ln (17)

Solve

(x - 2) ln (33) = 8 x ln (17) : x = \frac{2 ln ( 33 )}{ln ( 33 ) - 8 ln ( 17 )}

x = \frac{2 ln ( 33 )}{ln ( 33 ) - 8 ln ( 17 )}

57 = 2 7^{x}

2 = (0.0225)^{x}

4^{x^{6} - 5} = 1024

1 - e^{- 4 x} = 0.25

x, 4^{x} - 2 (8^{y}) = 0

What is the answer to 33^{x-2}=17^{8x} ?
The answer to 33^{x-2}=17^{8x} is x=(2ln(33))/(ln(33)-8ln(17))
Solve for x: 33^{x-2}=17^{8x}
The solution is x=(2ln(33))/(ln(33)-8ln(17))