What is the answer to 2^{4x+3}=10 ?

The answer to 2^{4x+3}=10 is x=(ln(5/4))/(4ln(2))

Solve for x: 2^{4x+3}=10

The solution is x=(ln(5/4))/(4ln(2))

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2^{4 x + 3} = 10

x = \frac{ln ( \frac{5}{4} )}{4 ln ( 2 )}

Decimal Notation

x = 0.08048 \dots

Solution steps

2^{4 x + 3} = 10

Apply exponent rules

(4 x + 3) ln (2) = ln (10)

Solve

(4 x + 3) ln (2) = ln (10) : x = \frac{ln ( \frac{5}{4} )}{4 ln ( 2 )}

x = \frac{ln ( \frac{5}{4} )}{4 ln ( 2 )}

5^{3 x - 1} - 4^{x + 1} = 0

2^{x} - 2^{1 - x} + 2^{0} = 0

e^{x} = 6^{x + 4}

4^{2 x + 1} - 4^{x + 2} = 128

4^{x (x)} = 4 (8^{x})

What is the answer to 2^{4x+3}=10 ?
The answer to 2^{4x+3}=10 is x=(ln(5/4))/(4ln(2))
Solve for x: 2^{4x+3}=10
The solution is x=(ln(5/4))/(4ln(2))