What is the answer to (1/8)^{x-3}=16^{4x-3} ?

The answer to (1/8)^{x-3}=16^{4x-3} is x= 21/19

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(1/8)^{x-3}=16^{4x-3}

(\frac{1}{8})^{x - 3} = 1 6^{4 x - 3}

x = \frac{21}{19}

Decimal Notation

x = 1.10526 \dots

Solution steps

(\frac{1}{8})^{x - 3} = 1 6^{4 x - 3}

Apply exponent rules

- 3 (x - 3) = 4 (4 x - 3)

Solve

- 3 (x - 3) = 4 (4 x - 3) : x = \frac{21}{19}

x = \frac{21}{19}

2^{k - 2} \cdot 5^{k - 2} = 100

5^{x + 5} = 7

5 \cdot 2^{x} = 1 0^{x}

e^{4 t} = 60

400 = 500 \cdot (1 - e^{- 0.16 t})

What is the answer to (1/8)^{x-3}=16^{4x-3} ?
The answer to (1/8)^{x-3}=16^{4x-3} is x= 21/19
Solve for x: (1/8)^{x-3}=16^{4x-3}
The solution is x= 21/19